JEE Mains · Chemistry · STD 11 - 6.2. Equilibrium - II (icon Equilibrium)
The stoichiometry and solubility product of a salt with the solubility curve given below is, respectively
- A \(\mathrm{X}_{2} \mathrm{Y}, 2 \times 10^{-9} \;\mathrm{M}^{3}\)
- B \(\mathrm{XY}_{2}, 1 \times 10^{-9} \;\mathrm{M}^{3}\)
- C \(\mathrm{XY}_{2}, 4 \times 10^{-9}\; \mathrm{M}^{3}\)
- D \(\mathrm{XY}, 2 \times 10^{-6} \;\mathrm{M}^{3}\)
Answer & Solution
Correct Answer
(C) \(\mathrm{XY}_{2}, 4 \times 10^{-9}\; \mathrm{M}^{3}\)
Step-by-step Solution
Detailed explanation
From the graph and dimensions salt is : \(\mathrm{XY}_{2}\) \([\mathrm{X}]=1 \times 10^{-3} \mathrm{M}\) \([\mathrm{Y}]=2 \times 10^{-3} \mathrm{M}\) \(\mathrm{XY}_{2}(\mathrm{s}) \rightleftharpoons \mathrm{X}_{(\mathrm{aq}, )}^{2+}+2 \mathrm{Y}_{(\mathrm{aq})}^{-}\)…
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