JEE Mains · Chemistry · STD 12 -1. Solution and colligative properties
Mass of ethylene glycol (antifreeze) to be added to \(18.6 \mathrm{~kg}\) of water to protect the freezing point at \(-24^{\circ} \mathrm{C}\) is _______ \(\mathrm{kg}\). (Molar mass in \(\mathrm{g} \mathrm{mol}^{-1}\) for ethylene glycol \(62, \mathrm{~K}_{\mathrm{f}}\) of water \(=1.86 \mathrm{~K} \mathrm{~kg} \mathrm{~mol}^{-1}\) )
- A \(15\)
- B \(10\)
- C \(9\)
- D \(8\)
Answer & Solution
Correct Answer
(A) \(15\)
Step-by-step Solution
Detailed explanation
\(\Delta \mathrm{T}_{\mathrm{f}}=\mathrm{i} \mathrm{K}_{\mathrm{f}} \times \text { molality }\) \(24=(1) \times 1.86 \times \frac{\mathrm{W}}{62 \times 18.6}\) \(\mathrm{~W}=14880 \mathrm{gm}\) \(=14.880 \mathrm{~kg}\)
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