JEE Mains · Chemistry · STD 11 - 5. Thermodynamics and thermochemistry
Let us consider an endothermic reaction which is non-spontaneous at the freezing point of water. However, the reaction is spontaneous at boiling point of water. Choose the correct option.
- A Both \(\Delta \mathrm{H}\) and \(\Delta \mathrm{S}\) are (-ve)
- B \(\Delta \mathrm{H}\) is (-ve) but \(\Delta \mathrm{S}\) is (+ve)
- C \(\Delta \mathrm{H}\) is \((+\mathrm{ve})\) but \(\Delta \mathrm{S}\) is \((-\mathrm{ve})\)
- D Both \(\Delta \mathrm{H}\) and \(\Delta \mathrm{S}\) are (+ve)
Answer & Solution
Correct Answer
(D) Both \(\Delta \mathrm{H}\) and \(\Delta \mathrm{S}\) are (+ve)
Step-by-step Solution
Detailed explanation
On increasing temperature, the given endothermic reaction becomes spontaneous. \(\Delta G=\Delta H-T \Delta S\) For spontaneity, \(\Delta \mathrm{G} 0\) So, \(\Delta \mathrm{S}\) should be +ve.
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