JEE Mains · Chemistry · STD 11 - 1. Some basic concept of chemistry
At \(300\, K\) and \(1\) atmospheric pressure, \(10\, mL\) of a hydrocarbon required \(55\, mL\) of \(O_2\) for complete combustion, and \(40\, mL\) of \(CO_2\) is formed. The formula of the hydrocarbon is
- A \(C_4H_{10}\)
- B \(C_4H_6\)
- C \(C_4H_7Cl\)
- D \(C_4H_8\)
Answer & Solution
Correct Answer
(B) \(C_4H_6\)
Step-by-step Solution
Detailed explanation
\(\mathop {{C_x}{H_y}}\limits_{10} + \mathop {\left( {x + \frac{y}{4}} \right){O_2}}\limits_{10\left( {x + \frac{y}{4}} \right)} \to \mathop {xC{O_2}}\limits_{10x} + \frac{y}{2}{H_2}O\) By given data, \(10\left( {x + \frac{y}{4}} \right) = 55....(1)\) \(10x = 40....(2)\)…
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