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JEE Mains · Chemistry · STD 11 - 2. structure of atom

Two positively charged particles \(m_{1}\) and \(m_{2}\) have been accelerated across the same potential difference of 200 keV as shown below.
image
[Given mass of \(m_{1} = 1 amu\) and \(m_{2} = 4 amu\)].
The deBroglie wavelength of \(m_{1}\) will be x times of \(m_{2}\). The value of x is __________ . (nearest integer)

  1. A 1
  2. B 2
  3. C 4
  4. D 0.5
Verified Solution

Answer & Solution

Correct Answer

(B) 2

Step-by-step Solution

Detailed explanation

\(\lambda_{ d }=\frac{ h }{\sqrt{2 mK.E.}}\) Here KE is same i.e. 200 k eV So \(\lambda_{ d } \propto \frac{1}{\sqrt{m}}\) \(\frac{\left(\lambda_{ d }\right)_{ m _1}}{\left(\lambda_{ d }\right)_{ m _2}}=\sqrt{\frac{ m _2}{m_1}}=\sqrt{4}=2\)…
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