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JEE Mains · Chemistry · STD 11 -p-Block elements - I
In graphite and diamond, the percentage of \(p-\) characters of the hybrid orbitals in hybridisation are respectively
- A \(33\) and \(25\)
- B \(67\) and \(75\)
- C \(50\) and \(75\)
- D \(33\) and \(75\)
Answer & Solution
Correct Answer
(B) \(67\) and \(75\)
Step-by-step Solution
Detailed explanation
\(\%\) of \(p-\) in graphite \({(sp)^2} = \frac{2}{3} \times 100 = 67\% \) \(\%\) of \(p-\) in diamond \({(sp)^3} = \frac{3}{4} \times 100 = 75\% \)
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