JEE Mains · Chemistry · STD 11 - 2. structure of atom
Arrange the following atomic orbitals of multi electron atoms in order of increasing energy.
A. \(n = 3, l = 2, m = +1\)
B. \(n = 4, l = 0, m = 0\)
C. \(n = 6, l = 1, m = 0\)
D. \(n = 5, l = 1, m = +1\)
E. \(n = 2, l = 1, m = +1\)
Choose the correct answer from the options given below:
- A \(C < D < B < A < E\)
- B \(B < A < E < C < D\)
- C \(E < C < D < B < A\)
- D \(E < B < A < D < C\)
Answer & Solution
Correct Answer
(D) \(E < B < A < D < C\)
Step-by-step Solution
Detailed explanation
The energy of an atomic orbital in a multi-electron atom is determined by the \((n + l)\) rule. Orbitals with a lower value of \((n + l)\) have lower energy. If two orbitals have the same \((n + l)\) value, the one with the lower \(n\) value has lower energy. Calculating the…
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