JEE Mains · Chemistry · STD 11 - 8.3. Organic chemistry purification and characterization
In Carius method of estimation of halogens, \(250 \,mg\) of an organic compound gave \(141 \,mg\) of \(AgBr.\) The percentage of bromine in the compound is : (at. mass \(Ag =108; Br = 80\))
- A \(48\)
- B \(60\)
- C \(24\)
- D \(36\)
Answer & Solution
Correct Answer
(C) \(24\)
Step-by-step Solution
Detailed explanation
Mass of substance \(=250 \mathrm{mg}=0.250 \mathrm{g}\) Mass of \(A g B r=141 \mathrm{mg}=0.141 \mathrm{g}\) \(1\; mole\) of \(A g B r=1\; g\) atom of \(B r\) \(188 g\) of \(A g B r=80 g\) of \(B r\) \(188 g\) of \(A g B r\) contain bromine \(=80 g\) \(0.141 g\) of \(A g B r\)…
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