JEE Mains · Physics · STD 12 - 10. Wave optics
The ratio of intensities at two points \(P\) and \(Q\) on the screen in a Young's double slit experiment where phase difference between two wave of same amplitude are \(\pi / 3\) and \(\pi / 2\), respectively are
- A \(1: 3\)
- B \(3: 1\)
- C \(3: 2\)
- D \(2: 3\)
Answer & Solution
Correct Answer
(C) \(3: 2\)
Step-by-step Solution
Detailed explanation
\(I _{ vet }= I _1+ I _2+2 \sqrt{ I _1 I _2} \cos \phi\) \(= I _0+ I _0+2 I _0 \cos \frac{\pi}{3}\) \(=2 I _0+2 I _0 \times \frac{1}{2}=3 I _0\) \(I _{\text {net }}= I _0+ I _0+2 I _0 \cos 90^{\circ}=2 I _0\) \(\text { Ratio }=\frac{3}{2}\)
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