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JEE Mains · Chemistry · STD 12 - 3. Chemical kinetics

Half life of zero order reaction \(\mathrm{A} \rightarrow\) product is 1 hour, when initial concentration of reaction is \(2.0 \mathrm{~mol} \mathrm{~L} \mathrm{~L}^{-1}\). The time required to decrease concentration of A from 0.50 to \(0.25 \mathrm{~mol} \mathrm{~L}^{-1}\) is _______.

  1. A 0.5 hour
  2. B 4 hour
  3. C 15 min
  4. D 60 min
Verified Solution

Answer & Solution

Correct Answer

(C) 15 min

Step-by-step Solution

Detailed explanation

For zero order reaction \(\begin{aligned} & \text { Half life }=\frac{A_o}{2 k} \\ & 60 \min =\frac{2}{2 k} \\ & k=\frac{1}{60} \mathrm{M} / \min \end{aligned}\) Now…
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