JEE Mains · Chemistry · STD 12 - 3. Chemical kinetics
Half life of zero order reaction \(\mathrm{A} \rightarrow\) product is 1 hour, when initial concentration of reaction is \(2.0 \mathrm{~mol} \mathrm{~L} \mathrm{~L}^{-1}\). The time required to decrease concentration of A from 0.50 to \(0.25 \mathrm{~mol} \mathrm{~L}^{-1}\) is _______.
- A 0.5 hour
- B 4 hour
- C 15 min
- D 60 min
Answer & Solution
Correct Answer
(C) 15 min
Step-by-step Solution
Detailed explanation
For zero order reaction \(\begin{aligned} & \text { Half life }=\frac{A_o}{2 k} \\ & 60 \min =\frac{2}{2 k} \\ & k=\frac{1}{60} \mathrm{M} / \min \end{aligned}\) Now…
See the Complete Solution
Get step-by-step explanations for this and 2.5 Lakh+ more JEE, NEET & CET questions.
- Unlock all solutions
- Practice the full chapter
- Track accuracy across PYQs
4.8 rated on Google Play · 14,000+ reviews
More questions from Chemistry
- A solution is prepared by dissolving 0.3 g of a non - volatile non - electrolyte solute 'A' of molar mass 60 g \( mol^{-1} \) and 0.9 g of a non - volatile non - electrolyte solute 'B' of molar mass 180 g \( mol^{-1} \) in 100 mL \( H_{2}O \) at \( 27^{\circ}C \). Osmotic pressure of the solution will be
[Given: \( R=0.082~L \) atm \( K^{-1} \) \( mol^{-1} \)]JEE Mains 2026 Medium - Given \((i)\,\,C\,({\rm{graphite}})\, + \,{O_2}{\kern 1pt} (g)\, \to \,C{O_2}\,(g);\,\Delta r{H^\circleddash} = x\,\,kJ\,mo{l^{ - 1}}\) \((ii)\,\,C\,({\rm{graphite}})\, + \,\frac{1}{2}{O_2}{\kern 1pt} (g)\, \to \,CO\,(g);\,\Delta r{H^\circleddash} = y\,\,kJ\,mo{l^{ - 1}}\) \((iii)\,\,CO\,(g)\, + \,\frac{1}{2}{O_2}{\kern 1pt} (g)\, \to \,C{O_2}\,(g);\,\Delta r{H^\circleddash} = z\,\,kJ\,mo{l^{ - 1}}\) Based on the above thermochemical equations, find out which one of the following algebraic relationships is correct?JEE Mains 2019 Hard
- Given below are two statements Statement \(I : CeO _{2}\) can be used for oxidation of aldehydes and ketones. Statement \(II :\) Aqueous solution of \(EuSO _{4}\) is a strong reducing agent. In the light of the above statements, choose the correct answer from the options given belowJEE Mains 2021 Medium
- Which one of the following arrangements represents the correct order of solubilities of sparingly soluble salts \(Hg_2Cl_2,\,\,Cr_2(SO_4 )_3,\,\,BaSO_4\) and \(CrCl_3\) respectively ?JEE Mains 2013 Hard
- Which of the following electronic configuration would be associated with the highest magnetic moment?JEE Mains 2024 Hard
- Match the LIST-I with LIST-II
LIST-I (Molecules/ion) LIST-II (Hybridisation of central atom) A. \(PF _5\) I. \(dsp ^2\) B. \(SF _6\) II. \(sp ^3 d\) C. \(Ni ( CO )_4\) III. \(sp ^3 d^2\) D. \(\left[ PtCl _4\right]^{2-}\) IV. \(sp ^3\)
Choose the correct answer from the options given belowJEE Mains 2025 Medium
More PYQs from JEE Mains
- Suppose \(f(x)=\frac{\left(2^x+2^{-x}\right) \tan x \sqrt{\tan ^{-1}\left(x^2-x+1\right)}}{\left(7 x^2+3 x+1\right)^3}\). Then the value of \(f^{\prime}(0)\) is equal toJEE Mains 2024 Hard
- The maximum value of the term independent of \('t'\) in the expansion of \(\left( tx ^{\frac{1}{5}}+\frac{(1- x )^{\frac{1}{10}}}{ t }\right)^{10}\) where \(x \in(0,1)\) isJEE Mains 2021 Hard
- A transverse wave is represented by \(y = \frac{{10}}{\pi }\,\sin \,\left( {\frac{{2\pi }}{T}t - \frac{{2\pi }}{\lambda }x} \right)\) For what value of the wavelength the wave velocity is twice the maximum particle velocity ..... \(cm\) ?JEE Mains 2014 Medium
- A small cube of side \(1\) mm is placed at the centre of a circular loop of radius \(10\) cm carrying a current of \(2\) A. The magnetic energy stored inside the cube is \(\alpha \times 10^{-14}\) J. The value of \(\alpha\) is _______. (\(\mu_o = 4\pi \times 10^{-7}\) Tm/A, \(\pi = 3.14\))JEE Mains 2026 Hard
- Let \(\alpha=\frac{(4 !) !}{(4 !)^{3 !}}\) and \(\beta=\frac{(5 !) !}{(5 !)^{4 !}}\). Then :JEE Mains 2024 Hard
- If the maximum load carried by an elevator is \(1400\,kg\) (\(600\,kg\) - Passenger \(+800\,kg\) - elevator), which is moving up with a uniform speed of \(3\,ms ^{-1}\) and the frictional force acting on it is \(2000\,N\), then the maximum 10.Power used by the motor is \(...........\,kW \left( g =10\,m / s ^2\right)\).JEE Mains 2023 Medium