ExamBro
ExamBro
JEE Mains · Chemistry · STD 12 - 2. Electrochemistry

दिया हैं : \(E^o_{Cr^{3+}/Cr} =-0.74\, V,\,\) \(E^o_{MnO_4^-/Mn^{2+}} =1.51 \,V\) \(E^o_{Cr_2O_7^{2-}/Cr^3+} =1.33\,V:\) \(E^o_{Cl/Cl^-} =1.36\,V\) दिये गए आँकड़ो के आधार पर प्रबल उपचायक होगा

  1. A \(Cl\)
  2. B \(Cr^{3+}\)
  3. C \(Mn^{2+}\)
  4. D \(MnO_4^-\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(MnO_4^-\)

Step-by-step Solution

Detailed explanation

Higher the value of standard reduction potential stronger will be the oxidising agent, hence \(M n O_{4}^-\) is the strongest oxidising agent.
Same subject
Explore more questions on app
From JEE Mains
Explore more questions on app