JEE Mains · Chemistry · STD 11 - 3. Classification of elements and periodicity in properties
Given below are two statements:
Statement I: The correct order of electronegativity of fluorine, oxygen and nitrogen is \(F > O > N\).
Statement II: The oxidation state of oxygen in OF\(_2\) is \(+2\) and in Na\(_2\)O is \(-2\).
In the light of the above statements, choose the correct answer from the options given below
- A Both Statement I and Statement II are true
- B Both Statement I and Statement II are false
- C Statement I is true but Statement II is false
- D Statement I is false but Statement II is true
Answer & Solution
Correct Answer
(A) Both Statement I and Statement II are true
Step-by-step Solution
Detailed explanation
Electronegativity increases across a period from left to right. Nitrogen, oxygen, and fluorine belong to group 15, 16, and 17 respectively in the second period. Thus, the correct order of electronegativity is \(F > O > N\). Statement I is true. In \(OF_2\), fluorine is more…
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