JEE Mains · Chemistry · STD 12 - 6. Haloalkanes and Haloarenes
Compound \(\mathrm{A}\) formed in the following reaction reacts with \(B\) gives the product \(C\). Find out \(A\) and \(B\).
- A \(\mathrm{A}=\mathrm{CH}_5-\mathrm{C} \equiv \overline{\mathrm{CNa}}{ }^{+}, \mathrm{B}=\mathrm{CH}_5-\mathrm{CH}_2-\mathrm{CH}_2-\mathrm{Br}\)
- B \(\mathrm{A}=\mathrm{CH}_3-\mathrm{CH}=\mathrm{CH}_2, \mathrm{~B}=\mathrm{CH}_3-\mathrm{CH}_2-\mathrm{CH}_2-\mathrm{Br}\)
- C \(\mathrm{A}=\mathrm{CH}_3-\mathrm{CH}_2-\mathrm{CH}_3, \mathrm{~B}=\mathrm{CH}_3-\mathrm{C} \equiv \mathrm{CH}\)
- D \(\mathrm{A}=\mathrm{CH}_3-\mathrm{C} \equiv \overline{\mathrm{CN}} \stackrel{+}{+}, \mathrm{B}=\mathrm{CH}_3-\mathrm{CH}_2-\mathrm{CH}_3\)
Answer & Solution
Correct Answer
(A) \(\mathrm{A}=\mathrm{CH}_5-\mathrm{C} \equiv \overline{\mathrm{CNa}}{ }^{+}, \mathrm{B}=\mathrm{CH}_5-\mathrm{CH}_2-\mathrm{CH}_2-\mathrm{Br}\)
Step-by-step Solution
Detailed explanation
\(\mathrm{CH}_3-\mathrm{C}=\mathrm{CH} \xrightarrow{\mathrm{Na}} \mathrm{CH}_3-\mathrm{C}=\mathrm{C}^{-} \mathrm{Na}^{+} \xrightarrow{\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{CH}_2-\mathrm{Br}} \downarrow\)…
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