JEE Mains · Chemistry · STD 11 - 1. Some basic concept of chemistry
Assume carbon burns according to following equation : \(2 C _{( s )}+ O _{2( g )} \rightarrow 2 CO ( g )\) When \(12\,g\) carbon is burnt in \(48\,g\) of oxygen, the volume of carbon monoxide produced is \(......\times 10^{-1}\,L\) at STP [nearest integer] [Given : Assume \(CO\) as ideal gas, Mass of \(C\) is \(12\,g\,mol ^{-1}\), Mass of \(O\) is \(16\,g\,mol ^{-1}\) and molar volume of an ideal gas at STP is \(22.7\,L\, mol ^{-1}\) ]
- A \(226\)
- B \(223\)
- C \(227\)
- D \(229\)
Answer & Solution
Correct Answer
(C) \(227\)
Step-by-step Solution
Detailed explanation
\(2 C ( s )+ O _2( g ) \rightarrow 2 CO ( g )\) \(1\,mol \qquad 1.5\,mol\) Limiting reagent is carbon. One mole carbon produces one mole CO. Hence, volume at STP is \(227 \times 10^{-1}\) litre
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