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JEE Mains · Chemistry · STD 11 - 1. Some basic concept of chemistry

Assume carbon burns according to following equation : \(2 C _{( s )}+ O _{2( g )} \rightarrow 2 CO ( g )\) When \(12\,g\) carbon is burnt in \(48\,g\) of oxygen, the volume of carbon monoxide produced is \(......\times 10^{-1}\,L\) at STP [nearest integer] [Given : Assume \(CO\) as ideal gas, Mass of \(C\) is \(12\,g\,mol ^{-1}\), Mass of \(O\) is \(16\,g\,mol ^{-1}\) and molar volume of an ideal gas at STP is \(22.7\,L\, mol ^{-1}\) ]

  1. A \(226\)
  2. B \(223\)
  3. C \(227\)
  4. D \(229\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(227\)

Step-by-step Solution

Detailed explanation

\(2 C ( s )+ O _2( g ) \rightarrow 2 CO ( g )\) \(1\,mol \qquad 1.5\,mol\) Limiting reagent is carbon. One mole carbon produces one mole CO. Hence, volume at STP is \(227 \times 10^{-1}\) litre
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