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JEE Mains · Chemistry · STD 11 - 5. Thermodynamics and thermochemistry
The reaction \(X \to Y\) is an exothermic reaction . Activation energy of the reaction for \(X\) into \(Y\) is \(150\,kJ\,mol^{-1}\) . Enthalpy of reaction is \(135\,kJ\,mol^{-1}\) . The activation energy for the reverse reaction, \(Y \to X\) will be.......\(kJ\,mol^{-1}\)
- A \(280\)
- B \(285\)
- C \(270\)
- D \(15\)
Answer & Solution
Correct Answer
(B) \(285\)
Step-by-step Solution
Detailed explanation
\(X \to Y;\,\Delta H = - 135\,kJ/mol,\) \({E_a} = 150\,kJ/mol\) For an exothermic reaction \({{E}_{a(F.R.)}}=\Delta H+E_{a(B.R.)}'\) \(150 = - 135 + E_{a(B.R.)}'\) \(E_{a(B.R.)}' = 285\,kJ/mol\)
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