JEE Mains · Chemistry · STD 11 - 5. Thermodynamics and thermochemistry
For the reaction \(\mathrm{A}(l) \rightarrow 2 \mathrm{B}(\mathrm{g})\) \(\Delta \mathrm{U}=2.1\; \mathrm{kcal}, \Delta \mathrm{S}=20\; \mathrm{cal} \mathrm{K}^{-1}\) at \(300\; \mathrm{K}\) Hence \(\Delta \mathrm{G}\) in \(\mathrm{kcal}\) is
- A \(-1.3\)
- B \(-2.7\)
- C \(-3.7\)
- D \(-4.2\)
Answer & Solution
Correct Answer
(B) \(-2.7\)
Step-by-step Solution
Detailed explanation
\(\mathrm{A}(\ell) \longrightarrow 2 \mathrm{B}(\mathrm{g})\) \(\Delta \mathrm{U}=2.1 \mathrm{Kcal}, \Delta \mathrm{S}=20 \mathrm{cal} \mathrm{K}^{-1}\) at \(300 \mathrm{K}\) \(\Delta \mathrm{H}=\Delta \mathrm{U}+\Delta \mathrm{n}_{\mathrm{g}} \mathrm{RT}\)…
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