JEE Mains · Chemistry · STD 12 -1. Solution and colligative properties
When \(9.45\, g\) of \(ClCH _{2} COOH\) is added to \(500\) \(mL\) of water, its freezing point drops by \(0.5^{\circ} C\). The dissociation constant of \(ClCH _{2} COOH\) is \(x \times 10^{-3}\). The value of \(x\) is ............... (Rounded off to the nearest integer) \(\left[ K _{ f \left( H _{2} O \right)}=1.86 \,K\, kg mol ^{-1}\right]\)
- A \(38\)
- B \(42\)
- C \(36\)
- D \(44\)
Answer & Solution
Correct Answer
(C) \(36\)
Step-by-step Solution
Detailed explanation
\(ClCH _{2} COOH \rightleftharpoons ClCH _{2} COO ^{\ominus}+ H ^{+}\) \(i =1+(2-1) \alpha\) \(i =1+\alpha\) \(\Delta T _{ f }= ik _{ f } m\) \(0.5=(1+\alpha)(1.86)\left(\frac{\left(\frac{9.45}{94.5}\right)}{\left(\frac{500}{1000}\right)}\right)\)…
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