JEE Mains · Chemistry · STD 12 - 9. Amines
Decarboxylation of all six possible forms of diaminobenzoic acids \(C _{6} H _{3}\left( NH _{2}\right)_{2} COOH\) yields three products \(A , B\) and \(C\). Three acids give a product \('A',\) two acids gives a product \('B'\) and one acid give a product \('C'.\) The melting point of product \('C'\) is .....\(^{\circ} C\).
- A \(63\)
- B \(90\)
- C \(104\)
- D \(142\)
Answer & Solution
Correct Answer
(D) \(142\)
Step-by-step Solution
Detailed explanation
\(M.P.\) \(142^{\circ} C\)
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