JEE Mains · Chemistry · STD 12 - 3. Chemical kinetics
For a first order reaction, the ratio of the time for \(75 \,\%\) completion of a reaction to the time for \(50\, \%\) completion is .... . (Integer answer)
- A \(4\)
- B \(1\)
- C \(3\)
- D \(2\)
Answer & Solution
Correct Answer
(D) \(2\)
Step-by-step Solution
Detailed explanation
\(\mathrm{k}=\frac{2.303}{\mathrm{t}} \log \frac{\mathrm{a}}{\mathrm{a}-\mathrm{x}}\) \(\frac{2.303}{\mathrm{t}_{50 \%}} \log \frac{100}{100-50}=\frac{2.303}{\mathrm{t}_{75 \%}} \log \frac{100}{100-75}\) \(\mathrm{t}_{75 \%}=2 \mathrm{t}_{50 \%}\)
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