JEE Mains · Chemistry · STD 11 - 6.2. Equilibrium - II (icon Equilibrium)
Two salts \(A _{2} X\) and \(MX\) have the same value of solubility product of \(4.0 \times 10^{-12}\). The ratio of their molar solubilities i.e. \(\frac{S\left(A_{2} X\right)}{S(M X)}=...........\) (Round off to the Nearest Integer).
- A \(40\)
- B \(50\)
- C \(45\)
- D \(55\)
Answer & Solution
Correct Answer
(B) \(50\)
Step-by-step Solution
Detailed explanation
For \(A _{2} X\) \(A _{2} X \rightarrow 2 A ^{+}+ X ^{2-}\) \(2 S _{1} \quad S _{1}\) \(K _{ sp }=4 S _{1}^{3}=4 \times 10^{-12}\) \(S _{1}=10^{-4}\) for \(MX\) \(MX \rightarrow M ^{+}+ X ^{-}\) \(\begin{array}{ll} S _{2} S _{2}\end{array}\)…
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