JEE Mains · Chemistry · STD 12 - 2. Electrochemistry
For a cell, \(Cu ( s ) \mid Cu ^{2+}\left(0.001 M || Ag ^{+}(0.01\,M ) \mid Ag ( s )\right.\) the cell potential is found to be \(0.43\,V\) at \(298 K\). The magnitude of standard electrode potential for \(Cu ^{2+} / Cu\) \(.........\times 10^{-2}\,V\) \(\left[\text { Given }: E _{ Ag ^{+} / Ag }^{\Theta}=0.80 V \text { and } \frac{2.303 \,RT }{ F }=0.06\,V \right]\)
- A \(33\)
- B \(32\)
- C \(34\)
- D \(31\)
Answer & Solution
Correct Answer
(C) \(34\)
Step-by-step Solution
Detailed explanation
At anode \(Cu \rightarrow Cu ^{2+}+2 e ^{-}\) At cathode \(2 Ag ^{+}+2 e ^{-} \rightarrow 2 Ag\) Cell reaction \(\rightarrow Cu +2 Ag ^{+} \rightarrow Cu ^{2+}+2 Ag\)…
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