JEE Mains · Chemistry · STD 12 - 5. Co-ordination chemistry
The total number of unpaired electrons present in the complex \(K _{3}\left[ Cr \right.\) (oxalate) \(\left._{3}\right]\) is ..........
- A \(3\)
- B \(9\)
- C \(7\)
- D \(2\)
Answer & Solution
Correct Answer
(A) \(3\)
Step-by-step Solution
Detailed explanation
\(K _{3}\left[ Cr (\text { oxalate })_{3}\right]\) Chromium is in \(+3\) oxidation state. Number of unpaired electrons in \(Cr ^{+3}\) will be \(3 .\)
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