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JEE Mains · Chemistry · STD 12 - 2. Electrochemistry

For the given reactions \(Sn ^{2+}+2 e ^{-} \rightarrow Sn\) \(Sn ^{4+}+4 e ^{-} \rightarrow Sn\) The electrode potentials are; \(E _{ Sn ^{2+} / Sn }^{\circ}=-0.140\, V\) and \(E _{ Sn ^{4+} / Sn }^{\circ}=0.010\, V\). The magnitude of standard electrode potential for \(Sn ^{4+} / Sn ^{2+}\) i.e. \(E _{ Sn ^{4+} / Sn ^{2+}}^{\circ}\) is \(.....\times 10^{-2}\, V\). (Nearest integer)

  1. A \(320\)
  2. B \(32\)
  3. C \(16\)
  4. D \(160\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(16\)

Step-by-step Solution

Detailed explanation

\(Sn ^{2+}+2 e ^{-} \rightarrow Sn \quad \Delta G _{1}^{0}=+2 \times 0.140 \times F\) \(Sn ^{+4}+4 e ^{-} \rightarrow Sn \quad \Delta G _{2}^{0}=-4 \times 0.01 \times F\) ____________________________________________…
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