JEE Mains · Chemistry · STD 11 - 6.1. Equilibrium - 1 (chemical Equilibrium)
Consider the reaction \(N _{2} O _{4}( g ) \rightleftharpoons 2 NO _{2}( g )\) The temperature at which \(K _{ C }=20.4\) and \(K _{ P }=600.1,\) is ....... \(K\). (Round off to the Nearest Integer). [Assume all gases are ideal and \(R =0.0831\, L\,bar \, K ^{-1} mol ^{-1}]\)
- A \(124\)
- B \(854\)
- C \(354\)
- D \(345\)
Answer & Solution
Correct Answer
(C) \(354\)
Step-by-step Solution
Detailed explanation
\(N _{2} O _{4}( g ) \rightleftharpoons 2 NO _{2}( g ) ; \Delta n _{ g }=2-1=1\) \(Now , K _{ p }= K _{ c } \cdot( RT )^{\Delta ng }\) or, \(600.1=20.4 \times(0.0831\, \times T )^{1}\) \(\therefore T =353.99\, K =354\, K\)
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