JEE Mains · Chemistry · STD 11 - 6.1. Equilibrium - 1 (chemical Equilibrium)
For the reaction \(\mathrm{A}+\mathrm{B} \rightleftharpoons 2 \mathrm{C}\) the value of equilibrium constant is \(100\) at \(298\, \mathrm{~K}\). If the initial concentration of all the three species is \(1\, \mathrm{M}\) each, then the equilibrium concentration of \(\mathrm{C}\) is \(\mathrm{X} \times 10^{-1} \,\mathrm{M}\). The value of \(\mathrm{x}\) is \(.....\) (Nearest integer)
- A \(25\)
- B \(30\)
- C \(35\)
- D \(40\)
Answer & Solution
Correct Answer
(A) \(25\)
Step-by-step Solution
Detailed explanation
\(\mathrm{A}+\mathrm{B} \rightleftharpoons2C\) \(1 \quad\;\; 1 \;\;\;\;\quad1\) \(-\mathrm{x}\) \(-\mathrm{x}\) \(\;\;\;\;2 \mathrm{x}\) _______________________ \(1-\mathrm{x}\) \(1-\mathrm{x}\) \(1+2 \mathrm{x}\)…
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