JEE Mains · Chemistry · STD 11 - 7. Redox reactions
Consider the reaction \({H_2}S{O_3}\left( {aq} \right) + S{n^{4 + }}\left( {aq} \right) + {H_2}O\left( l \right) \to S{n^{2 + }}\left( {aq} \right) + HSO_4^ - \left( {aq} \right) + 3{H^ + }\left( {aq} \right)\) Which of the following statements is correct?
- A \(Sn^{4+}\) is the oxidizing agent because it undergoes oxidation
- B \(Sn^{4+}\) is the reducing agent because it undergoes oxidatio
- C \(H_2SO_3\) is the reducing agent because it undergoes oxidation
- D \(H_2SO_3\) is the reducing agent because it undergoes reduction
Answer & Solution
Correct Answer
(C) \(H_2SO_3\) is the reducing agent because it undergoes oxidation
Step-by-step Solution
Detailed explanation
\(\mathop {{H_2}S{O_3}}\limits^{ + 4} (aq) + \mathop {Sn^{+4}} (aq) + {H_2}O(l) \to S{n^{2 + }}(aq) + \mathop {HS{O_4}^ - }\limits^{ + 6} (aq) + 3{H^ + }\) Hence \(H_2SO_3\) is the reducing agent because it undergoes oxidation
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