ExamBro
ExamBro
JEE Mains · Chemistry · STD 12 - 2. Electrochemistry

Consider the following reduction processes:
\(Al^{3+} + 3e^{-} \rightarrow Al(s), E^{\circ} = -1.66 V\)
\(Fe^{3+} + e^{-} \rightarrow Fe^{2+}, E^{\circ} = +0.77 V\)
\(Co^{3+} + e^{-} \rightarrow Co^{2+}, E^{\circ} = +1.81 V\)
\(Cr^{3+} + 3e^{-} \rightarrow Cr(s), E^{\circ} = -0.74 V\)
The tendency to act as reducing agent decreases in the order:

  1. A \(Al > Cr > Fe^{2+} > Co^{2+}\)
  2. B \(Al > Fe^{2+} > Cr > Co^{2+}\)
  3. C \(Al > Cr > Co^{2+} > Fe^{2+}\)
  4. D \(Cr > Fe^{2+} > Al > Co^{2+}\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(Al > Cr > Fe^{2+} > Co^{2+}\)

Step-by-step Solution

Detailed explanation

Reducing power \(\propto \frac{1}{\text { Reduction potential }}\)
Same subject
Explore more questions on app
From JEE Mains
Explore more questions on app