JEE Mains · Physics · STD 11 - 13. oscillations
A particle of mass \(0.50 \mathrm{~kg}\) executes simple harmonic motion under force \(\mathrm{F}=-50\left(\mathrm{Nm}^{-1}\right) \mathrm{x}\). The time period of oscillation is \(\frac{x}{35} s\). The value of \(x\) is _______. (Given \(\pi=\frac{22}{7}\) )
- A \(21\)
- B \(22\)
- C \(23\)
- D \(24\)
Answer & Solution
Correct Answer
(B) \(22\)
Step-by-step Solution
Detailed explanation
\(\mathrm{m}=0.5 \mathrm{~kg}\) \(\mathrm{~F}=-50(\mathrm{x})\) \(\mathrm{ma}=(-50 \mathrm{x})\) \(0.5 \mathrm{a}=-50 \mathrm{x}\) \(\mathrm{a}=(-100 \mathrm{x})\) \(\mathrm{W}^2=100 \Rightarrow(\mathrm{w}=10)\)…
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