JEE Mains · Chemistry · STD 11 - 7. Redox reactions
Conside the following reactions: \(\mathrm{NaCl}+\mathrm{K}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7}+\mathrm{H}_{2} \mathrm{SO}_{4}(\mathrm{Conc} .) \rightarrow(\mathrm{A})+\) Side products \((\mathrm{A})+\mathrm{NaOH} \rightarrow(\mathrm{B})+\) side product \((\mathrm{B})+\mathrm{H}_{2} \mathrm{SO}_{4}(\mathrm{dilute})+\mathrm{H}_{2} \mathrm{O}_{2} \rightarrow(\mathrm{C})+\) Side product The sum of the total number of atoms in one molecule each of \((A), (B)\) and \((C)\) is
- A \(14\)
- B \(16\)
- C \(18\)
- D \(20\)
Answer & Solution
Correct Answer
(C) \(18\)
Step-by-step Solution
Detailed explanation
\(4 \mathrm{NaCl}+\mathrm{K}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7}+6 \mathrm{H}_{2} \mathrm{SO}_{4}\) \(\quad \quad \quad \quad \quad \downarrow\) \(2 \mathrm{CrO}_{2} \mathrm{Cl}_{2}+4 \mathrm{NaHSO}_{4}+2 \mathrm{KHSO}_{4}+3 \mathrm{H}_{2} \mathrm{O}\) \((\mathrm{A})\)…
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