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JEE Mains · Physics · STD 12 - Electric charges and fields
  • JEE Mains 2019
  • Hard
  • MCQ

Three charges \(+Q, q, +Q\) are placed respectively, at distance, \(0, \frac d2\) and \(d\) from the origin, on the \(x-\) axis. If the net force experienced by \(+Q\), placed at \(x = 0\), is zero, then value of \(q\) is

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Answer & Solution

Correct Answer

(D) \(-\frac Q4\)

Step-by-step Solution

Detailed explanation

For equilibrium,

\(\vec{F}_{a}+\vec{F}_{B}=0\)

\(\vec{F}_{a}=-\overrightarrow{F_{B}}\)

\(\frac{k Q Q}{d^{2}}=-\frac{k Q q}{(d / 2)^{2}}\)

\(\Rightarrow q=-\frac{Q}{4}\)

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