JEE Mains · Chemistry · STD 11 - 1. Some basic concept of chemistry
A solution of sodium sulphate contains \(92\, g\) of \(Na^+\) ions per kilogram of water. The Molality of \(Na^+\) ions in that solution in \(mol\, kg^{-1}\) is
- A \(12\)
- B \(4\)
- C \(8\)
- D \(16\)
Answer & Solution
Correct Answer
(C) \(8\)
Step-by-step Solution
Detailed explanation
Molality of \(N{a^ + } = \left( {\frac{w}{M} \times \frac{{1000}}{w}} \right) \times 2\) (\(Na_2SO_4\) contains two \(Na^+\) ions) \( = \left[ {\left( {\frac{{92}}{{23}} \times \frac{{1000}}{{1000}}} \right)} \right] \times 2 = 8\)
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