JEE Mains · Chemistry · STD 12 -1. Solution and colligative properties
Liquid \(‘M’\) and liquid \(‘N’\) form an ideal solution. The vapour pressures of pure liquids \(‘M’\) and \(‘N’\) are \(450\) and \(700\,mmHg,\) respectively at the same temperature. Then correct statement is:
( \(x_M =\) mole fraction of \(‘M’\) in solution; \(x_N =\) mole fraction of \(‘N’\) in solution;
\(y_M =\) mole fraction of \(‘M’\) in vapour phase; \(y_N =\) mole fraction of \(‘M’\) in vapour phase)
- A \(\frac{{{x_M}}}{{{x_N}}} > \frac{{{y_M}}}{{{y_N}}}\)
- B \(\frac{{{x_M}}}{{{x_N}}} = \frac{{{y_M}}}{{{y_N}}}\)
- C \(({x_M} - {y_M})\, < {\kern 1pt} \,({x_N} - {y_N})\)
- D \(\frac{{{x_M}}}{{{x_N}}} < \frac{{{y_M}}}{{{y_N}}}\)
Answer & Solution
Correct Answer
(A) \(\frac{{{x_M}}}{{{x_N}}} > \frac{{{y_M}}}{{{y_N}}}\)
Step-by-step Solution
Detailed explanation
\(P_M^o\, = \,450\) \(P_N^o\, = \,700\) \({P_M}\, = \,{X_M}450\) \({P_N}\, = \,{X_N}700\) \({Y_M}{P_T}\, = \,{P_M}\) \({Y_N}{P_T}\, = \,{P_N}\) \(\frac{{{Y_M}{P_T}}}{{{Y_N}{P_T}}}\, = \,\frac{{{X_M}}}{{{X_N}}}\frac{{450}}{{700}}\)…
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