Copper reduces \(NO _{3}^{-}\) into \(NO\) and \(NO _{2}\) depending uponthe concentration of \(HNO _{3}\) insolution. (Assuming fixed \(\left[ Cu ^{2+}\right]\) and \(\left. P _{ NO }= P _{ NO _{2}}\right),\) the \(HNO _{3}\) concentration at which the thermodynamic tendency for reduction of \(NO _{3}^{-}\) into \(NO\) and \(NO _{2}\) by copper is same is \(10^{ x }\, M\). The value of \(2 x\) is ...... . \(\left[\right.\) Given \(, E_{C u^{2+} / C u}^{o}=0.34\, V , E _{ NO _{3}^{-} / NO_2 }^{\circ}=0.96\, V\) (Rounded-off to the nearest integer) \(E _{ NO _{3} / NO _{2}}^{\circ}=0.79 \,V\) and at \(298 \,K\)  \(\left.\frac{ RT }{ F }(2.303)=0.059\right]\)

1. A \(1\)
2. B \(2\)
3. C \(3\)
4. D \(4\)