JEE Mains · Chemistry · STD 12 - 5. Co-ordination chemistry
An aqueous solution of \(\mathrm{NiCl}_{2}\) was heated with excess sodium cyanide in presence of strong oxidizing agent to form \(\left[\mathrm{Ni}(\mathrm{CN})_{6}\right]^{2-}\). The total change in number of unpaired electrons on metal centre is \(.....\)
- A \(1\)
- B \(3\)
- C \(2\)
- D \(4\)
Answer & Solution
Correct Answer
(C) \(2\)
Step-by-step Solution
Detailed explanation
\(\left[\mathrm{Ni}(\mathrm{CN})_{6}\right]^{2-}\) \(\mathrm{Ni}^{+4} \rightarrow \mathrm{d}^{6}\) strong field ligand \([image(1)]\) Pairing will be there zero unpaired electron \(\mathrm{NiCl}_{2} \rightarrow \mathrm{Ni}^{2+} \rightarrow \mathrm{d}^{8}\) \([image(2)]\) Change…
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