JEE Mains · Chemistry · STD 11 - 6.1. Equilibrium - 1 (chemical Equilibrium)
A solid \(XY\) kept in an evacuated sealed container undergoes decomposition to form a mixture of gases \(X\) and \(Y\) at temperature \(T\). The equilibrium pressure is \(10\, bar\) in the vessel. \(K_p\) for this reaction is
- A \(25\)
- B \(100\)
- C \(10\)
- D \(5\)
Answer & Solution
Correct Answer
(A) \(25\)
Step-by-step Solution
Detailed explanation
\(XY(s) \leftrightarrow \mathop {X(g)}\limits_P + \mathop {Y(g)}\limits_P \) At eq., Total pressure \( = 2P = 10\,bar\) \(\therefore \,p = 5;\,Now\,{K_p} = ({P_x})({P_y}) = {p^2} = 25\)
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