JEE Mains · Chemistry · STD 11 - 1. Some basic concept of chemistry
A \(6.50\) molal solution of \(KOH\) \((aq.)\) has a density of \(1.89\, g\, cm ^{-3}\). The molarity of the solution is .......... \(mol\, dm ^{-3} .\) (Round off to the Nearest Integer). [Atomic masses: \(K : 39.0\, u ; O : 16.0 \,u ; H : 1.0\, u ]\)
- A \(3\)
- B \(4\)
- C \(9\)
- D \(7\)
Answer & Solution
Correct Answer
(C) \(9\)
Step-by-step Solution
Detailed explanation
\(6.5\) molal \(KOH =1000\, gm\) solvent has \(6.5\) moles \(KOH\) so wt of solute \(=6.5 \times 56\) \(=364\, gm\) wt of solution \(=1000+364=1364\) Volume of solution \(=\frac{1364}{1.89} m \ell\) Molarity…
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