JEE Mains · Chemistry · STD 12 - 2. Electrochemistry
In the cell \(Pt(s)| H_2 (g,1\,bar)| HCl(aq)| AgCl(s)| Ag(s)| Pt(s)\) the cell potential is \(0.92\,V\) when a \(10^{-6}\) molal \(HCl\) solution is used. The standard electrode potential of \((AgCl / Ag,Cl^- )\) electrode is ............. \(\mathrm{V}\) \(\left\{ {Given,\frac{{2.303RT}}{F} = 0.06\,V\,at\,298\,K} \right\}\)
- A \(0.94\)
- B \(0.76\)
- C \(0.40\)
- D \(0.20\)
Answer & Solution
Correct Answer
(D) \(0.20\)
Step-by-step Solution
Detailed explanation
\(E\, = \,{E^o}\, - \,0.06\,\log \,\frac{{[{H^ + }]\,[C{l^ - }]}}{{{{[{H_2}]}^{1/2}}}}\) \(0.92\, = \,{E^o}\, - \,0.06\,\log \,\frac{{{{10}^{ - 6}}\,.\,{{10}^{ - 6}}}}{{{1^{1/2}}}}\) \(0.92\, = \,{E^o}\, - \,0.06\,\log \,{10^{ - 12}}\) \({E^o} + \,\,0.06\, \times \,12\)…
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