JEE Mains · Chemistry · STD 12 - 2. Electrochemistry
A \(5.0\, m mol dm ^{-3}\) aqueous solution of \(KCl\) has a conductance of \(0.55\, mS\) when measured in a cell constant \(1.3 \,cm ^{-1}\). The molar conductivity of this solution is ....... \(mSm ^{2}\, mol ^{-1}\). (Round off to the Nearest Integer)
- A \(133\)
- B \(195\)
- C \(143\)
- D \(241\)
Answer & Solution
Correct Answer
(C) \(143\)
Step-by-step Solution
Detailed explanation
Given conc \(^{\text {n }}\) of \(KCl =\frac{ m . mol }{ L }\) : Conductance \(( G )=0.55 mS\) : Cell constant \(\left(\frac{\ell}{ A }\right)=1.3 cm ^{-1}\) To Calculate : Molar conductivity \(\left(\lambda_{ m }\right)\) of sol. \(\rightarrow\) Since…
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