JEE Mains · Chemistry · STD 11 - 6.1. Equilibrium - 1 (chemical Equilibrium)
If 50 mL of 0.5 M oxalic acid is required to neutralise 25 mL of NaOH solution, the amount of NaOH in 50 mL of given NaOH solution is __________ g.
- A 40
- B 50
- C 60
- D 70
Answer & Solution
Correct Answer
(A) 40
Step-by-step Solution
Detailed explanation
The reaction takes place as follows, \(H _2 C _2 O _4+2 NaOH \rightarrow Na _2 C _2 O _4+2 H _2 O\) Molarity \(=\frac{\text { Number of moles }}{\text { Volume of solution (in } L \text { ) }}\) Calculation: Now, 50 mL of \(0.5 M H _2 C _2 O _4\) is needed to neutralize 25 mL of…
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