JEE Mains · Chemistry · STD 12 -1. Solution and colligative properties
The vapour pressures of two volatile liquids \(A\) and \(B\) at \(25^{\circ} C\) are \(50\, Torr\) and \(100\, Torr,\) respectively. If the liquid mixture contains \(0.3\) mole fraction of \(A\), then the mole fraction of liquid \(B\) in the vapour phase is \(\frac{x}{17}\). The value of \(x\) is \(...\)
- A \(140\)
- B \(89\)
- C \(14\)
- D \(54\)
Answer & Solution
Correct Answer
(C) \(14\)
Step-by-step Solution
Detailed explanation
\(\frac{ y _{ B }}{1- y _{ B }}=\frac{ P _{ B }^{\circ}}{ P _{A}^{\circ}}\frac{ X _{ B }}{1- X _{ B }}\) \(\Rightarrow \frac{ y _{ B }}{1- y _{ B }}=\frac{100}{50}[\frac{0.7}{0.3}]=\frac{14}{3}\) \(\Rightarrow y _{ B }=\frac{14}{17}\) Ans. \(14\)
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