JEE Mains · Chemistry · STD 12 - 2. Electrochemistry
40 mL of a mixture of \(\mathrm{CH}_3 \mathrm{COOH}\) and HCl (aqueous solution) is titrated against 0.1 M NaOH solution conductometrically. Which of the following statement is correct?
- A The concentration of \(\mathrm{CH}_3 \mathrm{COOH}\) in the original mixture is 0.005 M
- B The concentration of HCl in the original mixture is 0.005 M
- C \(\mathrm{CH}_3 \mathrm{COOH}\) is neutralised first followed by neutralisation of HCl
- D Point ' C ' indicates the complete neutralisation HCl
Answer & Solution
Correct Answer
(B) The concentration of HCl in the original mixture is 0.005 M
Step-by-step Solution
Detailed explanation
From the given graph 2 ml NaOH solution is used for neutralisation of HCl and 3 ml NaOH solution is used for neutralisation of \(\mathrm{CH}_3 \mathrm{COOH}\). \(\therefore\) Mole of \(\mathrm{HCl}=\) Mole of NaOH used…
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