JEE Mains · Chemistry · STD 11 - 6.1. Equilibrium - 1 (chemical Equilibrium)
\(PCl _{5}\) dissociates as \(PCl _{5}( g ) \rightleftharpoons PCl _{3}( g )+ Cl _{2}( g )\) \(5\) moles of \(PCl _{5}\) are placed in a \(200\) \(litre\) vessel which contains \(2\, moles\) of \(N _{2}\) and is maintained at \(600 \,K\). The equilibrium pressure is \(2.46 \,atm\). The equilibrium constant \(K _{ p }\) for the dissociation of \(PCl _{5}\) is \(......\,\times 10^{-3}\). (nearest integer) (Given: \(R =0.082\, L \,atm \,K ^{-1} \,mol ^{-1}\) : Assume ideal gas behaviour)
- A \(2312\)
- B \(954\)
- C \(1107\)
- D \(1451\)
Answer & Solution
Correct Answer
(C) \(1107\)
Step-by-step Solution
Detailed explanation
Given : \(2\, mole\) of \(N _{2}\) gas was present as inert gas. Equilibrium pressure \(=2.46\, atm\) \(PCl _{5}( g ) \rightleftharpoons PCl _{3}( g )+ C \ell_{2}( g )\) \(t =0 \quad\quad\quad 5 \quad\quad\quad\quad 0\quad\quad 0\)…
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