ExamBro
ExamBro
JEE Mains · Chemistry · STD 11 - 6.1. Equilibrium - 1 (chemical Equilibrium)

\(4.0\,moles\) of argon and \(5.0\, moles\) of \(PCI _{5}\) are introduced into an evacuated flask of \(100\, litre\) capacity at \(610\, K\). The system is allowed to equilibrate. At equilibrium, the total pressure of mixture was found to be \(6.0 \,atm\). The \(K _{ p }\) for the reaction is ...... [Given : \(R=0.082 \,L \,atm\, K ^{-1}\, mol ^{-1}\) ]

  1. A \(2.25\)
  2. B \(6.24\)
  3. C \(12.13\)
  4. D \(15.24\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(2.25\)

Step-by-step Solution

Detailed explanation

\(PCl _{5}=5\) \(mole\) \(Ar =4\) \(mole\) \(P _{\text {Total }}=\frac{9 \times 0.82 \times 610}{100}=4.5 \,atm\) \(P _{ PCI _{5}}=\frac{5 \times 4.5}{9}=2.5 ; P _{ Ar }=\frac{4 \times 4.5}{9}=2\) \(PCl _{5} \rightleftharpoons PCl _{3}+ Cl _{2}\) \(2.5- P \quad P \quad P\)…
Same subject
Explore more questions on app
From JEE Mains
Explore more questions on app