JEE Mains · Physics · STD 11 - 13. oscillations
An object of mass \(0.5\, {kg}\) is executing simple harmonic motion. Its amplitude is \(5\, {cm}\) and time period (T) is \(0.2\, {s} .\) What will be the potential energy of the object at an instant \(t=\frac{T}{4}\) s starting from mean position. Assume that the initial phase of the oscillation is zero. (In \({J}\))
- A \(1.2\)
- B \(0.62\)
- C \(6.2\)
- D \(620\)
Answer & Solution
Correct Answer
(B) \(0.62\)
Step-by-step Solution
Detailed explanation
by using formula of time period \(T=2 \pi \sqrt{\frac{m}{k}}\) \(0.2=2 \pi \sqrt{\frac{0.5}{k}}\) \(k=50 \pi^{2}\) \(\approx 500\) \(x=A\, \sin (\omega t+\phi)\) \(=5\, c m\, \sin \left(\frac{\omega t}{4}+0\right)\) \(=5\, {cm} \sin \left(\frac{\pi}{2}\right)\) \(=5 \,{cm}\)…
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