JEE Mains · Chemistry · STD 11 - 4. Chemical bonding and molecular structure
The difference between bond orders of \(\mathrm{CO}\) and \(\mathrm{NO}\) is \(\mathrm{NO}^{\oplus}\) is \(\frac{\mathrm{x}}{2}\) where \(\mathrm{x}=.....\) (Round off to the Nearest Integer)
- A \(0\)
- B \(1\)
- C \(2\)
- D \(3\)
Answer & Solution
Correct Answer
(A) \(0\)
Step-by-step Solution
Detailed explanation
Bond order of \(\mathrm{CO}=3\) Bond order of \(\mathrm{NO}^{+}=3\) Difference \(=0=\frac{\mathrm{x}}{2}\) \(x=0\)
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