JEE Mains · Chemistry · STD 12 -1. Solution and colligative properties
\(2\) molal solution of a weak acid \(HA\) has a freezing point of \(3.885^{\circ} C\). The degree of dissociation of this acid is ........ \(\times 10^{-3} .\) (Round off to the Nearest Integer). [Given : Molal depression constant of water = \(1.85 \,K \,kg \,mol ^{-1}\) Freezing point of pure water \(\left.=0^{\circ} C \right]\)
- A \(50\)
- B \(60\)
- C \(55\)
- D \(65\)
Answer & Solution
Correct Answer
(A) \(50\)
Step-by-step Solution
Detailed explanation
\(\Delta T _{ f }=(1+\alpha) K _{ f } m\) \(\alpha=0.05=50 \times 10^{-3}\)
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