JEE Mains · Chemistry · STD 12 - 8.2 Carboxylic acids and their derivative
Complete the following reaction sequence and give the name of major product 'P'.
\(CH_3-CH_2-C\equiv N \xrightarrow[\text{(ii) } H_3O^+]{\text{(i) } OH^-/H_2O/\Delta} \xrightarrow[\text{(iv) } H_2O]{\text{(iii) } Cl_2/\text{Red P}} P \text{ (Major product)}\)
- A 2-Chloropropanoic acid
- B 3-Chloropropanoic acid
- C 1-Chloropropane
- D 2-Chloropropane
Answer & Solution
Correct Answer
(A) 2-Chloropropanoic acid
Step-by-step Solution
Detailed explanation
Step 1: Hydrolysis of the nitrile. Propanenitrile on basic hydrolysis followed by acidic workup gives propanoic acid: \(CH_3-CH_2-C \equiv N \xrightarrow[(ii)\ H_3O^+]{(i)\ OH^-/H_2O/\Delta} CH_3-CH_2-COOH\) Step 2: Hell\(-\)Volhard\(-\)Zelinsky (HVZ) reaction. Propanoic acid…
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