JEE Mains · Chemistry · STD 11 - 8.3. Organic chemistry purification and characterization
\(2.0\) g of a bromo hydrocarbon \((X)\) was subjected to Carius analysis, gave \(3.36\) g of \(AgBr\). The percentage of carbon in the compound \((X)\) is \(26.7\%\). Total number of carbon atoms in the empirical formula for compound \((X)\) is _____. (Given molar mass in g mol\(^{-1}\) H:\(1\), C:\(12\), Br:\(80\), Ag:\(108\))
- A 4
- B 5
- C 6
- D 7
Answer & Solution
Correct Answer
(B) 5
Step-by-step Solution
Detailed explanation
Mass of \(AgBr\) formed = \(3.36\) g Molar mass of \(AgBr = 108 + 80 = 188\) g mol\(^{-1}\) Moles of \(AgBr\) formed = \(\dfrac{3.36}{188} \approx 0.01787\) mol Since \(1\) mole of \(AgBr\) contains \(1\) mole of \(Br\), moles of \(Br\) in the compound = \(0.01787\) mol. Mass of…
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