JEE Mains · Chemistry · STD 11 - 5. Thermodynamics and thermochemistry
\(2.4\,g\) coal is burnt in a bomb calorimeter in excess of oxygen at \(298\,K\) and \(1\,atm\) pressure.The temperature of the calorimeter rises from \(298\,K\) to \(300\,K\). The enthalpy change during the combustion of coal is \(- x\,kJ\,mol ^{-1}\). The value of \(x\) is . (Nearest Integer)(Given : Heat capacity of bomb calorimeter \(20.0\,kJ\) \(K ^{-1}\). Assume coal to be pure carbon)
- A \(201\)
- B \(202\)
- C \(203\)
- D \(200\)
Answer & Solution
Correct Answer
(D) \(200\)
Step-by-step Solution
Detailed explanation
\(C ( s )+ O _{2}( g ) \rightarrow CO _{2}( g ) ; \Delta H =- x kJ / mole\) \(Q = C \Delta T =20\,kJ \times 2\) \(40\,kJ\) heat is released for \(2.4\,g\) of \(C\) For \(1\,mole\) ' \(C\) ' : \(\quad Q =\frac{40}{2.4} \times 12\)…
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