JEE Mains · Chemistry · STD 11 - 1. Some basic concept of chemistry
\(10.0 \,\mathrm{~mL}\) of \(0.05\, \mathrm{M}\, \mathrm{KMnO}_{4}\) solution was consumed in a titration with \(10.0\, \mathrm{~mL}\) of given oxalic acid dihydrate solution. The strength of given oxalic acid solution is \(.....\,\times 10^{-2} \,\mathrm{~g} / \mathrm{L}\) (Round off to the nearest integer)
- A \(1782\)
- B \(2152\)
- C \(1203\)
- D \(1575\)
Answer & Solution
Correct Answer
(D) \(1575\)
Step-by-step Solution
Detailed explanation
\(\mathrm{n}_{\mathrm{eq}} \mathrm{KMnO}_{4}=\mathrm{n}_{\text {eq }}=\mathrm{H}_{2} \mathrm{C}_{2} \mathrm{O}_{4} \cdot 2 \mathrm{H}_{2} \mathrm{O}\) or, \(\frac{10 \times 0.05}{1000} \times 5=\frac{10 \times \mathrm{M}}{1000} \times 2\) \(\therefore\) Conc. of oxalic acid…
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